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2a^2=90^2
We move all terms to the left:
2a^2-(90^2)=0
We add all the numbers together, and all the variables
2a^2-8100=0
a = 2; b = 0; c = -8100;
Δ = b2-4ac
Δ = 02-4·2·(-8100)
Δ = 64800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{64800}=\sqrt{32400*2}=\sqrt{32400}*\sqrt{2}=180\sqrt{2}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180\sqrt{2}}{2*2}=\frac{0-180\sqrt{2}}{4} =-\frac{180\sqrt{2}}{4} =-45\sqrt{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180\sqrt{2}}{2*2}=\frac{0+180\sqrt{2}}{4} =\frac{180\sqrt{2}}{4} =45\sqrt{2} $
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